Optimal. Leaf size=485 \[ -\frac{2 b n (e f-d g)^{5/2} \text{PolyLog}\left (2,1-\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}+\frac{2 \sqrt{f+g x} (e f-d g)^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (f+g x)^{3/2} (e f-d g) \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{92 b n \sqrt{f+g x} (e f-d g)^2}{15 e^3}-\frac{32 b n (f+g x)^{3/2} (e f-d g)}{45 e^2}+\frac{2 b n (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{92 b n (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}-\frac{4 b n (e f-d g)^{5/2} \log \left (\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right ) \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{e^{7/2}}-\frac{4 b n (f+g x)^{5/2}}{25 e} \]
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Rubi [A] time = 2.04509, antiderivative size = 485, normalized size of antiderivative = 1., number of steps used = 27, number of rules used = 14, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.452, Rules used = {2411, 2346, 63, 208, 2348, 12, 1587, 6741, 5984, 5918, 2402, 2315, 2319, 50} \[ -\frac{2 b n (e f-d g)^{5/2} \text{PolyLog}\left (2,1-\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}+\frac{2 \sqrt{f+g x} (e f-d g)^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (f+g x)^{3/2} (e f-d g) \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{92 b n \sqrt{f+g x} (e f-d g)^2}{15 e^3}-\frac{32 b n (f+g x)^{3/2} (e f-d g)}{45 e^2}+\frac{2 b n (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{92 b n (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}-\frac{4 b n (e f-d g)^{5/2} \log \left (\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right ) \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{e^{7/2}}-\frac{4 b n (f+g x)^{5/2}}{25 e} \]
Antiderivative was successfully verified.
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Rule 2411
Rule 2346
Rule 63
Rule 208
Rule 2348
Rule 12
Rule 1587
Rule 6741
Rule 5984
Rule 5918
Rule 2402
Rule 2315
Rule 2319
Rule 50
Rubi steps
\begin{align*} \int \frac{(f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{d+e x} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{5/2} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{e}\\ &=\frac{g \operatorname{Subst}\left (\int \left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{3/2} \left (a+b \log \left (c x^n\right )\right ) \, dx,x,d+e x\right )}{e^2}+\frac{(e f-d g) \operatorname{Subst}\left (\int \frac{\left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{e^2}\\ &=\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}+\frac{(g (e f-d g)) \operatorname{Subst}\left (\int \sqrt{\frac{e f-d g}{e}+\frac{g x}{e}} \left (a+b \log \left (c x^n\right )\right ) \, dx,x,d+e x\right )}{e^3}+\frac{(e f-d g)^2 \operatorname{Subst}\left (\int \frac{\sqrt{\frac{e f-d g}{e}+\frac{g x}{e}} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{e^3}-\frac{(2 b n) \operatorname{Subst}\left (\int \frac{\left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{5/2}}{x} \, dx,x,d+e x\right )}{5 e}\\ &=-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}+\frac{\left (g (e f-d g)^2\right ) \operatorname{Subst}\left (\int \frac{a+b \log \left (c x^n\right )}{\sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}} \, dx,x,d+e x\right )}{e^4}+\frac{(e f-d g)^3 \operatorname{Subst}\left (\int \frac{a+b \log \left (c x^n\right )}{x \sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}} \, dx,x,d+e x\right )}{e^4}-\frac{(2 b (e f-d g) n) \operatorname{Subst}\left (\int \frac{\left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{3/2}}{x} \, dx,x,d+e x\right )}{5 e^2}-\frac{(2 b (e f-d g) n) \operatorname{Subst}\left (\int \frac{\left (\frac{e f-d g}{e}+\frac{g x}{e}\right )^{3/2}}{x} \, dx,x,d+e x\right )}{3 e^2}\\ &=-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}-\frac{\left (2 b (e f-d g)^2 n\right ) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}}{x} \, dx,x,d+e x\right )}{5 e^3}-\frac{\left (2 b (e f-d g)^2 n\right ) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}}{x} \, dx,x,d+e x\right )}{3 e^3}-\frac{\left (2 b (e f-d g)^2 n\right ) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}}{x} \, dx,x,d+e x\right )}{e^3}-\frac{\left (b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int -\frac{2 \sqrt{e} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f-\frac{d g}{e}+\frac{g x}{e}}}{\sqrt{e f-d g}}\right )}{\sqrt{e f-d g} x} \, dx,x,d+e x\right )}{e^4}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}+\frac{\left (2 b (e f-d g)^{5/2} n\right ) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f-\frac{d g}{e}+\frac{g x}{e}}}{\sqrt{e f-d g}}\right )}{x} \, dx,x,d+e x\right )}{e^{7/2}}-\frac{\left (2 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}} \, dx,x,d+e x\right )}{5 e^4}-\frac{\left (2 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}} \, dx,x,d+e x\right )}{3 e^4}-\frac{\left (2 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{\frac{e f-d g}{e}+\frac{g x}{e}}} \, dx,x,d+e x\right )}{e^4}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}+\frac{\left (4 b (e f-d g)^{5/2} n\right ) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{e f-d g}}\right )}{d g+e \left (-f+x^2\right )} \, dx,x,\sqrt{f+g x}\right )}{e^{5/2}}-\frac{\left (4 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{e f-d g}{g}+\frac{e x^2}{g}} \, dx,x,\sqrt{f+g x}\right )}{5 e^3 g}-\frac{\left (4 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{e f-d g}{g}+\frac{e x^2}{g}} \, dx,x,\sqrt{f+g x}\right )}{3 e^3 g}-\frac{\left (4 b (e f-d g)^3 n\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{e f-d g}{g}+\frac{e x^2}{g}} \, dx,x,\sqrt{f+g x}\right )}{e^3 g}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{92 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}+\frac{\left (4 b (e f-d g)^{5/2} n\right ) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{e f-d g}}\right )}{-e f+d g+e x^2} \, dx,x,\sqrt{f+g x}\right )}{e^{5/2}}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{92 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}+\frac{2 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}-\frac{\left (4 b (e f-d g)^2 n\right ) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}\left (\frac{\sqrt{e} x}{\sqrt{e f-d g}}\right )}{1-\frac{\sqrt{e} x}{\sqrt{e f-d g}}} \, dx,x,\sqrt{f+g x}\right )}{e^3}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{92 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}+\frac{2 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}-\frac{4 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}+\frac{\left (4 b (e f-d g)^2 n\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-\frac{\sqrt{e} x}{\sqrt{e f-d g}}}\right )}{1-\frac{e x^2}{e f-d g}} \, dx,x,\sqrt{f+g x}\right )}{e^3}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{92 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}+\frac{2 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}-\frac{4 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}-\frac{\left (4 b (e f-d g)^{5/2} n\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}\\ &=-\frac{92 b (e f-d g)^2 n \sqrt{f+g x}}{15 e^3}-\frac{32 b (e f-d g) n (f+g x)^{3/2}}{45 e^2}-\frac{4 b n (f+g x)^{5/2}}{25 e}+\frac{92 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )}{15 e^{7/2}}+\frac{2 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )^2}{e^{7/2}}+\frac{2 (e f-d g)^2 \sqrt{f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^3}+\frac{2 (e f-d g) (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{3 e^2}+\frac{2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e}-\frac{2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{e^{7/2}}-\frac{4 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right ) \log \left (\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}-\frac{2 b (e f-d g)^{5/2} n \text{Li}_2\left (1-\frac{2}{1-\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}}\right )}{e^{7/2}}\\ \end{align*}
Mathematica [A] time = 1.09493, size = 818, normalized size = 1.69 \[ \frac{450 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\sqrt{e f-d g}-\sqrt{e} \sqrt{f+g x}\right ) (e f-d g)^{5/2}-450 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\sqrt{e f-d g}+\sqrt{e} \sqrt{f+g x}\right ) (e f-d g)^{5/2}-225 b n \left (\log \left (\sqrt{e f-d g}-\sqrt{e} \sqrt{f+g x}\right ) \left (\log \left (\sqrt{e f-d g}-\sqrt{e} \sqrt{f+g x}\right )+2 \log \left (\frac{1}{2} \left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}+1\right )\right )\right )+2 \text{PolyLog}\left (2,\frac{1}{2}-\frac{\sqrt{e} \sqrt{f+g x}}{2 \sqrt{e f-d g}}\right )\right ) (e f-d g)^{5/2}+225 b n \left (\log \left (\sqrt{e f-d g}+\sqrt{e} \sqrt{f+g x}\right ) \left (\log \left (\sqrt{e f-d g}+\sqrt{e} \sqrt{f+g x}\right )+2 \log \left (\frac{1}{2}-\frac{\sqrt{e} \sqrt{f+g x}}{2 \sqrt{e f-d g}}\right )\right )+2 \text{PolyLog}\left (2,\frac{1}{2} \left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}+1\right )\right )\right ) (e f-d g)^{5/2}-1800 b n \left (\sqrt{e} \sqrt{f+g x}-\sqrt{e f-d g} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )\right ) (e f-d g)^2+900 b \sqrt{e} \sqrt{f+g x} \log \left (c (d+e x)^n\right ) (e f-d g)^2+900 a \sqrt{e} \sqrt{f+g x} (e f-d g)^2-200 b n \left (\sqrt{e} \sqrt{f+g x} (4 e f-3 d g+e g x)-3 (e f-d g)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )\right ) (e f-d g)+300 e^{3/2} (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right ) (e f-d g)-24 b n \left (3 e^{5/2} (f+g x)^{5/2}+5 (e f-d g) \left (\sqrt{e} \sqrt{f+g x} (4 e f-3 d g+e g x)-3 (e f-d g)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{e} \sqrt{f+g x}}{\sqrt{e f-d g}}\right )\right )\right )+180 e^{5/2} (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{450 e^{7/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 1.205, size = 0, normalized size = 0. \begin{align*} \int{\frac{a+b\ln \left ( c \left ( ex+d \right ) ^{n} \right ) }{ex+d} \left ( gx+f \right ) ^{{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b g^{2} x^{2} + 2 \, b f g x + b f^{2}\right )} \sqrt{g x + f} \log \left ({\left (e x + d\right )}^{n} c\right ) +{\left (a g^{2} x^{2} + 2 \, a f g x + a f^{2}\right )} \sqrt{g x + f}}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (g x + f\right )}^{\frac{5}{2}}{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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